8x^2+2x+4=-x^2-10x

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Solution for 8x^2+2x+4=-x^2-10x equation: 



8x^2+2x+4=-x^2-10x

We move all terms to the left:

8x^2+2x+4-(-x^2-10x)=0

We get rid of parentheses

8x^2+x^2+10x+2x+4=0

We add all the numbers together, and all the variables

9x^2+12x+4=0

a = 9; b = 12; c = +4;
Δ = b2-4ac
Δ = 122-4·9·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{18}=-2/3$

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